kx(x-2 root 5) 10

0:02:45

For what value of k are the roots of the quadratic equation `kx(x-2sqrt(5))+10=0` real and equal?

0:03:42

For what value of K the roots of the quadratic equation kx(x-2 root 5) + 10 are Equal?

0:04:34

Find values of k for equation kx(x - 2√5) + 10 = 0 real and equal

0:03:16

Forhat value of k are the roots of the quadratic equation k x(x-2 √(5))+10=0 real and equal?

0:03:23

For what value of k are the roots of Quadratic equation kx(x-2√5)+10=0 real and equal. #Cbse10 #impo

0:00:57

Quadratic Equations IIT Questions No 05 ( X Class)

0:00:50

Quadratic Equations IIT Questions No 11 ( X Class)

0:03:35

Find the Value of K for which the Quadratic has Equal Roots - Quick and Simple Explanation

0:00:42

СЛОЖИТЕ ДВА КОРНЯ

0:02:47

find the value of k the roots of the quadratic equations kx( x - 2√5) +10 = 0 are equal? #class10

0:03:04

If `x= - 5 ` is a root of the quadratic equation `kx^(2) + 13x - 10 = 0 `, then complete

0:01:08

If 1/2 is a root of the equation x^2+kx 5/4=0, find the value of k | Quadratic Equation

0:02:32

Find the value of K for which the quadratic equation Kx (x-2) + 6 = 0 has two equal roots

0:00:48

Functions IIT Questions NO 11 ( X Class)

0:03:32

Find constant k for quadratic equation with double root. x^2 -kx +5 =0.

0:06:17

Find the Value of k in Quadratic Equations when One Root is Given | Step-by-Step Explanation

0:02:19

Find the value of K for which the quadratic equation kx(x-2)+6=0 has equal roots, class 10

0:02:08

If the equation kx(x-2)+6 =0 has equal roots. Find the value of k.

0:00:32

find the value of quadratic equation kx^2-14x+8=0 for which one root is 6times the other ?class 10

0:04:12

14. Find the value of k for quadratic equation kx (x – 2) + 6 = 0 having equal roots.

0:01:55

If x=1/2 is a root of the equation x²+kx-5/4=0 then find the value of k @edulover123

0:03:27

Find the values of 'k' in[ kx(x - 2) + 6 = 0 ], so that they've two equal roots | QUADRATIC EQUATION

0:03:30

Find the value of K which Have two Equal Roots kx(x-2) + 6 = 0

0:00:16

This chapter closes now, for the next one to begin. 🥂✨.#iitbombay #convocation